[SOLVED] Pivot nominal values

Kate_StrydomKate_Strydom MemberPosts:19Contributor I
edited June 2020 inHelp
Hi,

This is the format of my data

ID DOB device_mac

1 1993-02-08 2c:5a:05:a4:0O:c8
1 1993-02-08 94:eb:cd:17:22:9c

I would like to to be in the following format

ID DOB device_mac_1 device_mac_2

1 1993-02-08 2c:5a:05:a4:0O:c8 94:eb:cd:17:22:9c

is it possible to do this in RapidMiner? The pivot operator does not seem to be able to produce this?!

Can anyone suggest how I would tackle this?

Thanks.
Kate
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Answers

  • MartinLiebigMartinLiebig Administrator, Moderator, Employee, RapidMiner Certified Analyst, RapidMiner Certified Expert, University ProfessorPosts:3,381RM Data Scientist
    Hi Kate!

    I think Pivot is the way to go. The only thing is that you have two Group by Attributes (ID and DOB). How do you want to use them? Both fitting? Then you need to construct ID+DOB (strings) and join the individual values afterwards.

    Best,
    Martin
    - Head of Data Science Services at RapidMiner -
    Dortmund, Germany
  • Kate_StrydomKate_Strydom MemberPosts:19Contributor I
    Hi Martin,

    I finally have the desired output:)．我不得不使用循环值和附加自由进出rators from a previous question before I used the pivot operator. I have always used a aggregate operator when using the pivot operator so this was a new experience & has developed my RM skills.

    [shadow=red,left]Previous question:http://rapid-i.com/rapidforum/index.php/topic,8438.msg28539.html#msg28539．[/shadow]

    This means I can now create a profile in one line for each of my ID numbers.

    Thanks.
    Kate
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